Question

A steel sphere of mass 100 gm moving with a
velocity of 4 m/s collides with a dust particle
elastically moving in the same direction with
a velocity of 1 m/s. The velocity of the dust
particle after the collision is
1) 8 m/s 2) 7 m/s 3) 6 m/s
4) 9 m/s​

Answer 1

Answer:

Mjobajo akmakomankana ajkamkķoajjaokaòajjaln

Answer 2

Answer:

Vel.are given by the equations as belows after the collision.

Vb= [2mu+U(m--M)]/(M+m)

(Above equation is for the sphere ball.Vb is final Vel after collision,m is mass of the dust particle,u is initial Vel. Of dust particle,U is initial Vel. Of sphere,M is mass of the sphere)

Vd= =[ 2MU+u(m-M)]/(,M+m)

[Here Vd is Vel. Of dust particle. after collision.]

When large mass( in this case the sphere M collides with very very small mass( in this case the dustbparticle m as compared to the sphere) collides elastically as given

mass of the small particle is neglected.Considering elastic collision where the momentum& ke are both conserved we can get the vel.of smal particle with equation the 2nd equation

as below

Vd=( 2MU- M) Since m isnegligible, u is 1)

Vd= (2×0.1×4–0.1)/0.1

Vd= 8–1= 7 m/s

Vd= 7m/s

=