A steel spherical ball is meted to make 8 new identical balls. find the ratio of radius of each small ball to original one
Answers
Answered by
0
Big sphere:
R=Rcm
Small sphere:
r=rcm
Number of small spheres · Volume of small sphere=Volume of big sphere
n · (4/3)πr^3=(4/3)πR^3
(4/3)πr^3=(1/n)
(4/3)πR^3
(4/3) and π get canceled.
r^3 = 1
R^3 8
On cube root,
r = 1
R 2
Therefore the ratio of each small sphere: big sphere is r:R is 1:2
R=Rcm
Small sphere:
r=rcm
Number of small spheres · Volume of small sphere=Volume of big sphere
n · (4/3)πr^3=(4/3)πR^3
(4/3)πr^3=(1/n)
(4/3)πR^3
(4/3) and π get canceled.
r^3 = 1
R^3 8
On cube root,
r = 1
R 2
Therefore the ratio of each small sphere: big sphere is r:R is 1:2
Similar questions
Social Sciences,
8 months ago
English,
8 months ago
English,
8 months ago
Math,
1 year ago
Math,
1 year ago
Biology,
1 year ago
Computer Science,
1 year ago