a steel tape is calibrated at 20 C. on a cold day when the temperature is -15C , percentage error in the tape will be ( αsteel = 1.2 * 10^-5 C -1
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change in temperature=20-(-15)=35C
decrease in length=1+a×t×l=(1.2×10^-5×35×l)=0.00042l
percentage error=0.00042l/l×100
=0.00042×100
=0.042%
decrease in length=1+a×t×l=(1.2×10^-5×35×l)=0.00042l
percentage error=0.00042l/l×100
=0.00042×100
=0.042%
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