A steel wire 20mm in diameter is stretched by a force of 113N.the tensile stress applied is:
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Answer:
Explanation:
Correct option is
A
1.273×10
7
N/m
2
given diameter = 1mm
⇒ radius of wire
=0.5×10
−3
m
=5×10
−4
m
Force applied =10 N
∴ Stress =
π×25×10
−8
10
=0.1273×10
8
Stress =1.273×10
7
N/m
2
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