Question

A steel wire 3 m long when subjected to a tensile load of 40 kgf extends through 6 cm. If Y of steel is
2 × 1011 N m– 2
, calculate (i) stress, (ii) strain and (m) area of cross-section of the wire.

Answer 1

Answer:

calculate using= force *length/area* delta length

Answer 2

Answer:

strain=0.02

stress=4*10^9

a=3*10^-7

Explanation:

stress = y*Strain

strain = change in length/original length

Y=FL/Al