Question

A steel wire hangs vertically under its own weight ifd density is 8000 kg/m^3 and allowabke stress is 2000 kg/cm^2 then how mucj length it can sustain

Answer 1

A steel wire hangs vertically under its own weight. If its density is 8000 kg/m³ and allowable stress is 2000 kg/cm² then how much length it can sustain.

stress = 2000 kg/cm² , it is possible as you know basically, unit of stress is N/m² . if I assume it is written as 2000g N/cm² .

we know, stress = force applied/area

for a steel wire which is hanged vertically , force applied = weight = mg

mass = volume × density

e.g., m = Vd = ALd [ where , A is cross sectional area and L is length ]

now, stress = ALd/A = Lgd

or, 2000g N/cm² = L × g × 8000kg/m³ [ given density , d = 8000 kg/m³ ]

or, 2000 × 10⁴ = 8000L

or, L = 2500 m