A steel wire of 40m in length is stretched through 2.0mm. The cross sectional area of the wire is 2.0mm2 . If young's modulus of steel is 2.0×1011N/m2 the energy density of wire is
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U=12×stress×strain
=12×y×(stain)2 [strain=ΔLL]
=12×2.0×1011×(2×10−34)2
=2.5×104J/m3
Hence a is the correct answer.
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