Question

A steel wire of length 1.5 m and
diameter A.25 cm is ioaded with
a force of 98 N. The increase in
length of the wire is
1.5 x 10-a m. Calculate the tensiie
stress and the fractional change
in iength of the wire.

Answer 1

Hello Dear,

◆ Answer -

Fractional change in length of wire = 10^-8

◆ Explanation -

Cross sectional area of wire is -

A = πr^2

A = 3.142 × (0.25/2)^2

A = 0.049 m^2

Tensile stress of steel wire is calculated as -

Stress = F / A

Stress = 98 / 0.049

Stress = 2000 N/m^2

Fractional change in length of wire is given by -

Strain = l/L

Strain = Stress / Y

Strain = 2000 / 2×10^11

Strain = 10^-8

Therefore, fractional change in length of wire is 10^-8.

Thanks dear...

Answer 2

Answer:

answer in the attachment

Explanation:

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