Question

A steel wire of length 4m and diameter 5mm is stretched by 5 kg-wt . find the increase in its length ,if the uoung modulus of steel wire is 2.4×10 power 12 dyne-cm-2

Answer 1

Here is your answer =0.00005m

Answer 2

Solution:-

Given

l = 4cm

2r = 5mm => r= 2.5mm = 0.25cm

f=5kg-wt

f=  = 5×1000 g-wt  

f= 5000g-wt ×960D

y= 2.4×10^12 dyne cm∧2

Δl =?

Y= $\frac{F}{\pi R^{2} Y}$×$\frac{l}{Δl}$

Δl= Fl/$\pi$r∧2y

=>5000×980×400/22/7×(0.25)∧2×2.4×10∧12

=>Δl= 0.0041cm

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@GauravSaxena01