A steering wheel of diameter 0.5 m is rotate anticlockwise by applying teo force each of magnitude 5n. draw a diagram to show the application of force and calculate the moment of the force applied. if you don't know this answer please don't answer wrong answer will be reported
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Given that diameter of 0.5 m wheel for which we are applying a force of 5N.
We know that moment of force is given by r×F
here, d=0.5m
r=0.5/2 m
=0.25m
F=5N
Now there are two forces and from right-hand thumb rule their moments will get added,
Hence moment=0.25m×5N+0.25m×5N
=1.25Nm+1.25Nm
=2.5Nm.
Hence we have a magnitude of 2.5Nm.
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Answer:
moment of couple= either force×couple arm
= 5N×0.5m
= 2.5NM
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