A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 5 N. Calculate the moment of the
forces applied.
(If can draw the diagram to show the application of forces)
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Answers
The moment of force applied is 2.5 N-m
The moment of force applied is 2.5 N-mExplanation:
The moment of force applied is 2.5 N-mExplanation:Given data:
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.N
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:Moment of couple = Either of force x Couple arm
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:Moment of couple = Either of force x Couple armMoment of couple = 5 N x 0.5 m
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:Moment of couple = Either of force x Couple armMoment of couple = 5 N x 0.5 mMoment of couple = 2.5 N-m
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:Moment of couple = Either of force x Couple armMoment of couple = 5 N x 0.5 mMoment of couple = 2.5 N-mThus the moment of force applied is 2.5 N-m
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:Moment of couple = Either of force x Couple armMoment of couple = 5 N x 0.5 mMoment of couple = 2.5 N-mThus the moment of force applied is 2.5 N-mAlso learn more
The moment of force applied is 2.5 N-mExplanation:Given data:Diameter of wheel "d" = 0.5 mMagnitude of force = 5.NTo find: moment of force "F" = ?Solution:Moment of couple = Either of force x Couple armMoment of couple = 5 N x 0.5 mMoment of couple = 2.5 N-mThus the moment of force applied is 2.5 N-mAlso learn moreA key is 5 cm long and turns a levers of the lock at the distance of 1 cm. If the lock is opened by an effort of 10 N, calculate the resistance offered by the levers of the lock.?
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