Question

a stell rod use for break operation is 1.50 long when it is subjected to a tensile force the exyension produced is 0.5mm find strain. please solve it's very important question... ​

Answer 1

Answer:

strain is ratio of change in length to original length so strain equals (1.5-0.5×10^3)/1.5

Answer 2

Answer:

The strain produced in the rod is 3.3×10⁻⁴.

Explanation:

We will use the following formulas to solve the question which is given as,

$S=\frac{\Delta L}{L}$         (1)

From the question we have,

S=strain produced in the steel rod

ΔL=change in the length of the rod

L=length of the rod

From the question we have,

ΔL=0.5mm=0.5×10⁻³m

L=1.50m

By substituting the value of ΔL and L in equation (1) we get;

$S=\frac{0.5\times 10^-^3}{1.50}$

$S=3.3\times 10^-^4$

Hence, the strain produced in the rod is 3.3×10⁻⁴.