Question

a step up transformer has turn ratio 10:1 a cell of e.m.f 5volt is fed to the primary then secondary voltage

Answer 1

Emf(primary)/Emf(secondary)=Turns ratio
10/1=5/Emf(secondary)
then Emf(secondary)=0.5V

Answer 2

Answer:

The secondary voltage of the transformer is 50 volt.

Explanation:

The relation between turn ratio and voltage ratio for a transformer is given as,

$\frac{N_s}{N_p}=\frac{V_s}{V_p}$        (1)

Where,

$N_s$=number of turns in the secondary windings

$N_p$=number of turns in the primary windings

$V_s$=voltage across the secondary windings

$V_p$=voltage across the primary windings

For a step-up transformer, the number of turns in the secondary is greater than the number of turns in the primary windings.

From the question we have,

$\frac{N_s}{N_p}=\frac{10}{1}$       (2)

$V_p=5\ volts$   (3)

We get the following by putting equations (2) and (3) in equation (1):

$\frac{10}{1}=\frac{V_s}{5}$

$V_s=50 \ volt$

Hence, the secondary voltage of the transformer is 50 volt.

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