Question

A stone A is let fall from the tower ,a second stone B is thrown downwards after 2 seconds with the initial speed of 20m/s .if both stones A and B hits ground simultaneously find the height of the tower.​

Answer 1

Answer:

I dropped ⇒ initial velocity =0

⇒ time will be given by h=

2

1

gt

2

t=

g

2h

=

10 m/s

2

2×20 m

=2 sec

II both reaches simultaneous be so ti,e taken by IInd stone will be

2 sec−1 sec=1 sec

or

t

′

=1 sec

putting it in h=ut'+

2

1

gt

2

& h=20 m,g=10m/s

2

we get

20=u×1+5×1

⇒

u=15 m/s