A stone dropped down a deep well from rest . The well is 50 m deep . How long it reach the bottom of the well . Given a =9.8m2
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h = ut + 0.5*g*t^2
u (initial speed} = 0 m/s,
50 = 0.5*9.81*t^2
t^2 = 50/(0.5*9.81)
solve for t for the answer.
u (initial speed} = 0 m/s,
50 = 0.5*9.81*t^2
t^2 = 50/(0.5*9.81)
solve for t for the answer.
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