Question

A stone dropped down from a height hits the ground at the 4th second. Calculate the velocity with which it hits

the ground and the height from which it is dropped. (a=10m/s2).​

Answer 1

Explanation:

let the initial velocity = 0

acceleration = 10 m/s^2

time taken = 4 sec

distance = ut +1/2at^2

= 0×4+1/2×10×16

= 80 m

final velocity = initial velocity + acceleration ×time

= u + at

= 0+ 10×4

= 40 m/s

I HOPE YOU GOT THE ANSWERS