A stone dropped from a building of height h reaches the ground in time t seconds. From the same building if two stones are thrown (one upwards and the other downwards) with the same speed uu and they reach the ground after t_{1}t 1 seconds and t_{2}t 2 seconds respectively. Then the relation between the tt, t_{1}t 1 and t_{2}t 2 is
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A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown( one upwards and one downwards ) with the same velocity u and they reach the earth surface after t1 and t3 seconds respectively , then 1) t= t1 - t2. 2) t = t1+ t2 ÷2. 3) t=√t1t2.Nov 24, 2018
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