A stone dropped from a height of 19.66m took 2 second to reach the ground. What is the value of g here?
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Answer:
The value of g = 9.83 m/s²
Explanation:
The distance traveled by the stone when it is dropped, S = 19.66 m
Time taken to reach ground, t = 2 s
The initial velocity of the stone, u = 0 m/s
From the 2nd equation of motion:
S = ut + (at²)/2
⇒ a = (S - ut) (2/t²)
a = (19.66 - (0 × 2)) (2/2²)
a = 19.66 / 2
a = 9.83 m/s²
This acceleration, 'a' will be equal to the acceleration due to gravity of the planet since the stone is under free fall.
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