Physics, asked by ajsal65, 6 months ago


A stone dropped from a height of 19.66m took 2 second to reach the ground. What is the value of g here?​

Answers

Answered by Johnsonmijo
2

Answer:

The value of g = 9.83 m/s²

Explanation:

The distance traveled by the stone when it is dropped, S = 19.66 m

Time taken to reach ground, t = 2 s

The initial velocity of the stone, u = 0 m/s

From the 2nd equation of motion:

S = ut + (at²)/2

⇒ a = (S - ut) (2/t²)

   a = (19.66 - (0 × 2)) (2/2²)

   a = 19.66 / 2

   a = 9.83 m/s²

This acceleration, 'a' will be equal to the acceleration due to gravity of the planet since the stone is under free fall.

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