A stone dropped from a roof of a building takes 4 sec to reach ground. Calculate height of building. (take g=10m/s)
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Answered by
36
initial velocity = 0
time taken = 4s
acceleration = g = 10m/s^2
using 2nd equation of motion
s= ut +(1/2)at^2
=(1/2)(10)(4)(4)
= 80
As the distance travelled by the stone would be equal to the height of building.
So, the height of the building was 80m .
time taken = 4s
acceleration = g = 10m/s^2
using 2nd equation of motion
s= ut +(1/2)at^2
=(1/2)(10)(4)(4)
= 80
As the distance travelled by the stone would be equal to the height of building.
So, the height of the building was 80m .
Answered by
13
Hiii..
Given: Initial velocity=0
Time taken=4 sec
Acceleration=g=10m/s^2
Using equation 2nd
s=ut+1/2at^2
s=(1/2)(10)(4)(4)
s=80
So it's given distance travelled means the height of building...
Therefore the height is 80m...
Hope it help you..!!
Given: Initial velocity=0
Time taken=4 sec
Acceleration=g=10m/s^2
Using equation 2nd
s=ut+1/2at^2
s=(1/2)(10)(4)(4)
s=80
So it's given distance travelled means the height of building...
Therefore the height is 80m...
Hope it help you..!!
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