Question

a stone dropped from a window reaches the ground in 0.5 seconds calculate its speed just before it hits the ground . what is its average speed during 0.5 second. calculate the height of Window from the ground.

Answer 1

hiii

Initial speed (u) = 0  (as the stone is at rest)
Time = 0.5 seconds
Acceleration = 9.8m/s² 
i) According to first equation of motion:v = u + at
v = 0 + 9.8 x 0.5v = 4.9 m/s
This is the speed just before stone hits the ground
ii) According to third equation of motion :v² = u² + 2as
(4.9)² = 0 + 2 x 9.8 x s24.01 = 19.6ss = 1.225
so the average speed = 1.225/0.5 = 2.45m/s
iii) Height of window from the ground
Height = 1.225m
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Answer 2

Here,

Initial speed, u = 0

Acceleration, a = 9.8 m/s2

Time, t = 0.5 s

(i)

Using, v = u + at

=> v = 0 + (9.8)(0.5)

=> v = 4.9 m/s

This is the speed when the stone reaches the ground.

(ii)

Distance traveled, s = ut + ½ at2

=> s = 0 + ½ (9.8)(0.5)2

=> s = 1.225 m

So, average speed = 1.225/0.5 = 2.45 m/s

(iii)

Height of window from the ground is 1.225 m




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