Question

a stone dropped from a window reaches the ground in 0.5 second (given g=10 ms-2).a) calculate the speed just before it hits the ground. b) Calculate the height of window from the ground c) what is the average speed during 0.5 second

Answer 1

X/tpow2=a
So x=10*0.25
X=2.5meters(height of the window)
V=a*t
V=10*0.5=5m/s(speed)
AvgV=5/2=2.5(avg speed)

Answer 2

time= 0.5 sec
g=10m/s^2
u=0
v=?
(a) v=u+gt
v=0+10×0.5
v=5m/s ans

(b) h= ut+1/2gt^2

h=0+1/2×10×(0.5)^2
h=1.25m ans