Question

A stone dropped from the top of a tower 300 m high splashes into water of pound near base of water . When the splash heard at the top ?

Answer 1

speed of sound in air is 320 m /s

distance = 300

time = distance / speed

time = 300/320

t =.93

hope this help

Answer 2

✰ Correct Question✰

▪A stone dropped from the top of a tower 300 m high splashes into water of pound near base of water . When the splash heard at the top ?(Speed of sound in air is 340m/s)

✰ Answer ✰

➧Given :-

▪ Height of tower (h) =300m

▪ Initial velocity (u) =0 m/s

▪Acceleration due to gravity (g) = 9.8m/s^2

▪Speed of sound in air = 340m/s

To Find :-

➤The time taken to splash heard at the top??

✰Solution ✰

➠ By using this formula

➠ S=ut+1/2 gt^2

➠ 300m=0×t+ 1/2 ×9.8×t^2

➠ 300m = 4.9×t^2

➠ 300/4.9=t^2

➠t=√300 ×2.9

➠t=7.2 sec. ...................(1)

Now,

➠ Time taken by sound to reach the top of the tower.

▪ Time taken (t')= distance covered by sound /speed of sound .

➠ t' =300/340= 0.88s

➠ t'=0.88s...............(2)

Adding equation (1) and (2) we get,

t+t' = 7.2s+ 0.88s = 8.08s

∴ time taken to splash heard at the top of tower =8.08s.

✰Additional information ✰

▪Motion of body moving freely under gravity can be calculate by using this formula ▪

➧(1) v=u+gt

➧(2) s= ut +1/2 gt^2

➧(3) v^2=u^2+gs

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