Question

A stone falling from the top of a vertical tower has descended xm when another is let to fall from a point y m below the top. If they fall from rest and reach ground together, find the height of the tower. (Answer isn't (x+y)^2/4x)​

Answer 1

Answer:

A stone falling from the top of a vertical lower has descended x metre when another is dropped from a point y metre, below the top. If they fall from rest and reach the ground together, show that the height of the tower is 4x(x+y)2m.

hpe it help you

Answer 2

Explanation:

Answer

Total time taken by first stone to reach the ground

t=

g

2h

Time taken by the 1

st

stone to descend height x is

t

1

=

g

2x

Time taken by 2

nd

stone to reach the ground

t

2

=

g

2(h−y)

As per the question

t−t

1

=t

2

g

2h

−

g

2x

=

g

2(h−y)

On simplification

2h

−

2x

=

2(h−y)

Aquaring both sides

2h+2x−2(

2h

)(

2x

)=2(h−y)

2x+2y=4

hx

x+y=2

hx

on squaring

4x

(x+y)

2