Question

A stone falls freely under gravity .It covers distance h1 h2 and h3 in 5 seconda

Answer 1

Answer:

using, S= ut + 1/2gt² and V = u+at

now, 1st 5s at h1= 1/2 * g * 25=12.5 g and V1=5 gm

where h1 is the distance and v1 is the velocity in 5s,if innitial velocity(u)=0

simillarly,

at h2=5g*5+1/2*g*25=37.5 g and V2=10g

at h3=10g*5+ 1/2*g*25=62.5g and V3=15g

and, also we find the relation as h3=h1 + h2 +12.5g