A train takes 2 hours less for a journey of 300 km if its speed is increased by 5 km/h from its usual speed . Find the usual speed of the train .
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Answer:
25km
Explanation:
distance 300km now speed is increased
speed x km/h new speed (x+5) km/h
time taken 300/x h new time 300/x+5 h
atq,300/x-300/x+5=2
300x+1500-300x/x2(square)+5x=2
1500=2x2(square)+10x
x2+10x-750=0
x2+30x-25x-750=0
x(x+30)-25(x+30)=0
(x-25)(x+30)=0
X=25 km/h as speed cant be -ve
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