A stone falls freely under gravity. It covers
distances hi, he and h3 in the first 5 seconds,
the next 5 seconds and the next 5 seconds
respectively. The relation between hi, he and
(2013]
h3 is
h2 _h3
5
(a) hi - 3
(b) h2 = 3h, and h3 = 3h2
h = h2 = h3
(c)
h = 2h2 = 3h3
(d)
Answers
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Answer and Explanation :
The options which you have given are not clear so I have assumed h1 , h2 , h3 heights for first 5 second , next 5 second and next 5 seconds respectively.
By Galileo's Law of odd numbers,
the ratio of heights covered in 1st , 2nd , 3rd seconds is 1:3:5 provided constant acceleration and equal intervals of time.
Therefore, here h1:h2:h3 = 1:3:5
Hence, 3 x h1 = h2
and 5 x h2 = 3 x h3
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