Question

A stone falls from a balloon that is descending at a uniform rate of 12m/s. The displacent of the stone from the point of release after 10 seconds is

Answer 1

Answer:

Ten seconds after release of the stone, it would have fallen by a displacement of 610 m.

Explanation:

Since the stone was released from the balloon descending at a uniform velocity, the initial velocity of the stone is

u = 12m/s

After release, the stone is in free fall under the influence of gravity. Hence its acceleration is acceleration due to gravity

a = g = 9.8$m/s^{2}$

We have to calculate the displacement after 10 seconds. So

t = 10s

With the given data, displacement (s) can be calculated by using the second equation of motion, that is,

$s = ut + \frac{1}{2} at^{2}$

  = 12 × 10 + $\frac{1}{2}$ × 9.8 × 10²

  = 120 + 490

  = 610m