Physics, asked by Shreya268, 1 year ago

a stone falls from a balloon that is descending at a uniform rate of 12m/s. the displacement of the stone after 10s of its release is

Answers

Answered by Hetarth4
31
Here acceleration (a) will be gravity=9.8m/s^2
u =12m/s
time=10seconds

S(distance)=ut+0.5at×t
=12×10+0.5×9.8×10×10
=120+0.5×980
=120+490
=610metres.....

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Shreya268: the answer is 610 m
Answered by ItzNorah
14

Hi mate

A stone falls from a balloon that is descending at a uniform rate of 12m/s. the displacement of the stone after 10s of its release is (g=9.8m/s²)

Solution:

Here acceleration (a) will be gravity

u = 12m/s

time = 10 seconds

S(distance) = ut + 0.5at × t

= 12 × 10 + 0.5 × 9.8 × 10 × 10

= 120 + 0.5 × 980

= 120 + 490

= 610 meter

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