a stone falls from a balloon that is descending at a uniform rate of 12m/s. the displacement of the stone after 10s of its release is
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Answered by
31
Here acceleration (a) will be gravity=9.8m/s^2
u =12m/s
time=10seconds
S(distance)=ut+0.5at×t
=12×10+0.5×9.8×10×10
=120+0.5×980
=120+490
=610metres.....
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u =12m/s
time=10seconds
S(distance)=ut+0.5at×t
=12×10+0.5×9.8×10×10
=120+0.5×980
=120+490
=610metres.....
If you find it helpful please mark it brainliest..
Shreya268:
the answer is 610 m
Answered by
14
Hi mate
A stone falls from a balloon that is descending at a uniform rate of 12m/s. the displacement of the stone after 10s of its release is (g=9.8m/s²)
Solution:
Here acceleration (a) will be gravity
u = 12m/s
time = 10 seconds
S(distance) = ut + 0.5at × t
= 12 × 10 + 0.5 × 9.8 × 10 × 10
= 120 + 0.5 × 980
= 120 + 490
= 610 meter
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