Question

a stone falls from a building and reaches ground 3s later.What's the height of the building? (g=10m/s^2)

Answer 1

Explanation:

We have,

Initial speed of the stone, u = 0 m/s

Time taken by the stone to reach ground, t = 3s

Height of the building = distance travelled by the stone = s = ?

Acceleration due to gravity, g = 10 m/s²

Using $\sf{s = ut-\frac{1}{2}gt^{2}}$, we get,

$\implies{\sf{s = 0-\frac{1}{2}\times{10}\times{3}^{2}}}$

$\implies{\sf{s = -5\times{9}}}$

$\implies{\boxed{\sf{s = -45 \:m}}}$

Therefore, the height of the building = 45 m

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