Question

A stone has a mass of 112.5 gram when the stone totally immersed in water contained in measuring cylinder is placed water from 50 cm cube to 95 cm cube find the density of the stone​

Answer 1

Answer:2.5 gcm^-3

Explanation:

We know mass of stone (m) = 112.5g

Thew original volume of water in cylinde (v1)=50 cm^3

The new volume of water in cylinder after the stone is immersed(v2)= 95cm^3

The volume of stone(v) = v2-v1 = 95-50 = 45cm^3

Density of stone = Mass/Volume =m/v = 112.5/45 = 2.5 gcm^-3

Answer 2

Answer:

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