Question

A stone is allowed to fall from the top of a tower 100 M high at the same time another stone is projected vertically downwards from the ground with a velocity of 25 m per second sq. Calculate when and where the two stones will meet. (g = 10m/s)

Answer 1

answer is 21.6 m above the ground

solution is in picture

hope this is helpful

Answer 2

Question :

A stone is allowed to fall from the top of a tower 100 M high at the same time another stone is projected vertically downwards from the ground with a velocity of 25 m per second sq. Calculate when and where the two stones will meet. (g = 10m/s)

Solution :

Let stone 1 be allowed to fall from the top of a tower a which is 100 M high..It undergoes free fall with u1 = 0 and a 1 = 10m/s².

Let stone to be projected vertically upwards from point P on the ground where U2 = 25 m and a2 = -10m/s².

Let the point where the two stones will meet = C at time to at a height y from the ground (100-y) from the top of a tower.

For full solution refer to the above attachments.