Question

A stone is allowed to fall from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25m/s. Calculate when and where the two stones will meet?

Answer 1

hey here is your answer _______

relative displacement=100m

relative initial velocity ={0-(-25)}=25m/s

relative acceleration ={(-10)-(-10)}=(-10+10)=0

S=ut +1/2at^2

100=25t

t=4sec

Answer 2

here is your ans for this question