A stone is dropped by a person from the top of a building, which is 200 m tall. At the same time, another stone is thrown upwards, with a velocity of 50 m s.–1 by a person standing at the foot of the building. Find the time after which the two stones meet.
ur ans is t=4s
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Answer:
d = speed×time
200= 50 × t
200/50= 4
t= 4
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