Question

A stone is dropped freely, while another
thrown vertically downward with an initial
velocity of 2ms from the same point.
simultaneously. The time required by them
to have a distance of separation 22 m
between them is
(A) 11s
(B) 5.5 s
(C) 44s
(D) 22s​

Answer 1

Answer:

v = 2m/s

Separation distance = 22m

= 22/2

= 11s

11 Seconds is Required.

hole it helps you,

Answer 2

Answer:

let this happens after t seconds then

s=0×t+1/2 gt^2 and

s' =2t+1/2 gt^2

by question s'-s=22

so

(2t +1/2gt^2)-(1/2gt^2)=22

2t=22

t=11 second