Question

a stone is dropped from a height, covers 72m in last one sec of its journey the distance .the distance it covers in the middle of one second of its journey

Answer 1

Explanation:

Let the total height of the tower is h and the total time is taken to reach the ground is t.

The height is given as,

h=

2

1

gt

2

(1)

The height before last seconds is given as,

h−24.5=

2

1

g(t−1)

2

2

1

gt

2

−24.5=

2

1

g(t)

2

+

2

1

g−gt

t=3s

Substitute the value of t in the equation (1), we get

h=

2

1

×9.8(3)

2

h=44.1m

Thus, the height of the tower is 44.1m.