A stone is dropped from a height of 100 m while
another one is projected vertically upwards from
the ground with a velocity of 25 m/s at the same
time. The time in seconds after which they will
have the same height is (acceleration due to
gravity g = 10 ms-2)
1) 4 2 5 3 6 4 7
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Answer:
4s
Explanation:
distance travelled by 1st body downwards
= 1/2 ×g× t^2
height of 1st body is
H1= 100- 1/2× g× t^2
height or distance by 2nd body
H2 = ut - 1/2×g×t^2
( g is -ve as it is moving up)
H1 = H2
therefore t= 4s
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