Question

A stone is dropped from a height of 100 m while
another one is projected vertically upwards from
the ground with a velocity of 25 m/s at the same
time. The time in seconds after which they will
have the same height is (acceleration due to
gravity g = 10 ms-2)
1) 4 2 5 3 6 4 7​

Answer 1

Answer:

4s

Explanation:

distance travelled by 1st body downwards

= 1/2 ×g× t^2

height of 1st body is

H1= 100- 1/2× g× t^2

height or distance by 2nd body

H2 = ut - 1/2×g×t^2

( g is -ve as it is moving up)

H1 = H2

therefore t= 4s