Question

a stone is dropped,from a height of 196m.calculate time taken to fall.how fast does it move at the end of this fall?Acceleration after 1 sec.

Answer 1

h = 196m
u = 0

T = √2h/g = √2×196/9.8 = √40 =2√10 sec

v =√2gh = √2×9.8×196 = 19.6√10 m/s

acceleration is always same; that is 9.8 m/s^2