A stone is dropped from a height of 20m. a) How long will it take to reach the ground? b) what will be its speed when it hits the ground? (g=10ms^-2)
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u=0
s=20m
a=10m/s^-2
t=?
using 2nd equation of motion
s=ut+1/2at^2
20=(0*t)+(1/2*10*t^2)
20=10/2*t^2
20*2/10=t^2
t^2=4
**t=2 sec**
speed=distance/time
speed=20/2
**speed=10m/s**
s=20m
a=10m/s^-2
t=?
using 2nd equation of motion
s=ut+1/2at^2
20=(0*t)+(1/2*10*t^2)
20=10/2*t^2
20*2/10=t^2
t^2=4
**t=2 sec**
speed=distance/time
speed=20/2
**speed=10m/s**
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