Question

A stone is dropped from a height of 50m. Calculate b) final velocity just fore touching the ground (v) Clues : u =0, s = 50m, g=9.8 m/s^2

Answer 1

Answer:

Explanation:

So v=?,u=0,g=9.8m/s²,s=50m

So applying third equation of motion:

v²=u+2as

v²=0+2*50*9.8

v= (980)^1/2

V=31.30m/s

Answer 2

we know that vsquare = 2gh

v= root(2gh)

v=root(2(9.8)(50))

v=31.304

if g=10,

v=10(root10)

please mark me as brainliest plz