Question

A stone is dropped from a height of 50m. Calculate its velocity just before it touches the
ground. (take g=10m/ s^2 )

Answer 1

Answer:

v= 31.622m/s

Explanation:

when it strikes the ground the velocity becomes Zero the velocity before it strikes the ground is

$v = \sqrt{2gh } \\ = \sqrt{2 \times 10 \times 50} \\ = \sqrt{1000 } \\ = 31.622 \frac{m}{s}$