A stone is dropped from a tower. What will be its speed when its height is 100m.
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Answer:
The stone is dropped from the cliff. So,
Initial Speed = u=0
Distance = s=100m
Final Speed = v
Acceleration = a = g = 9.8 sec2m
Now,
v2=u2+2as
v2=0+2∗9.8∗100
v=(2∗9.8∗100)
v=44.7secm
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