Question

a stone is dropped from edge of a roof . find the speed of the stone at 2 s after the stone was dropped

Answer 1

Hii...


u=0
t=2
g=9.8


by using first equation of motion

v=u+at

v=19.6m/s

Answer 2

Question:

A stone is dropped from the edge of a roof.Find the speed of the stone at 2s after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.