a stone is dropped from height of 20 m. a) how long will take to reach the ground? b)what will be its speed when it hits the ground? The value of g is 10 metre per second square
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v²-u²=2as
V= final velocity(?)
U= Initial velocity (zero)
a = acceleration (10m/s given)
s = Distance to be travelled( 20mts.)
U(initial vel.) Is zero, because the stone is thrown without any I initial push, it's just thrown from the rest.
So:-
v²-(0)²=2(10).(20)
>v²=20.20 =400
>v= 20
V=U+AT
>20=0+10T
>T=2sec
I hope this will help you
V= final velocity(?)
U= Initial velocity (zero)
a = acceleration (10m/s given)
s = Distance to be travelled( 20mts.)
U(initial vel.) Is zero, because the stone is thrown without any I initial push, it's just thrown from the rest.
So:-
v²-(0)²=2(10).(20)
>v²=20.20 =400
>v= 20
V=U+AT
>20=0+10T
>T=2sec
I hope this will help you
SrivastavaDEEPAK:
I ask you to tell me what will be it's speed when it hits the ground?
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