A stone is dropped from height of 20 m . find its velocity just before touching the ground
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Answer:
The velocity just before touching the ground = 20 m/s.
Explanation:
h = 20 m (Given)
u = 0 m/s (the object was at rest)
g = 10 m/s^2
Using the third equation of motion, 2(g)(h) = v^2 - u^2
2(10)(20) = v^2 - 0^2
it implies, 400 = v^2
it implies, v = 20 m/s
Therefore, the velocity just before touching the ground = 20 m/s
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