Question

A stone is dropped from height of 20 m . find its velocity just before touching the ground​

Answer 1

Answer:

The velocity just before touching the ground = 20 m/s.

Explanation:

h = 20 m (Given)

u = 0 m/s (the object was at rest)

g = 10 m/s^2

Using the third equation of motion, 2(g)(h) = v^2 - u^2

2(10)(20) = v^2 - 0^2

it implies, 400 = v^2

it implies,  v = 20 m/s

Therefore, the velocity just before touching the ground = 20 m/s

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