A stone is dropped from the edge of the roof. (A) how long does it take to fall 4.9m. how fast does it move at the end of the fall. What is the acc. After 1 and 2sec?
Answers
Answered by
3
Heyy mate ❤✌✌❤
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Given;
u = 0 m/s.
g = 9.8 m/s ^2
s = 4.9m
Now,
S = ut + 1/2 g t^2
=> 4.9 = 0 × t + 1/2 × 9.8 × t^2
=> 4.9 = 0 + 4.9 ×t^2
=> 4.9/4.9 = t^2
=> t^2 = 1.
=> t =1.
✔✔✔
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Given;
u = 0 m/s.
g = 9.8 m/s ^2
s = 4.9m
Now,
S = ut + 1/2 g t^2
=> 4.9 = 0 × t + 1/2 × 9.8 × t^2
=> 4.9 = 0 + 4.9 ×t^2
=> 4.9/4.9 = t^2
=> t^2 = 1.
=> t =1.
✔✔✔
Answered by
2
Explanation:
a stone is dropped from the age of the roof and take it to fall 4.9 at the end of the 2 seconds
Similar questions