a stone is dropped from the edge of the roof. it passes a window 2m high in 0.1 sec. how far is the roof above the top of the window
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Answer:
19.0125 m.
Explanation:
let H 1 be the distance of the roof above the top of the window
and H 2 be the distance of the roof above the bottom of the window
H 2 = gt2²/2
H 1 = gt1²/2
H 2 - H 1 = g/2 ( t2² - t1² ) = 5 ( t2² - t1² ) = 2
2 = 5( t2² - t1² ) = 5( t2² - t1² ) = 5 ( t2 - t1 ) ( t2 + t1 )
2 = 5 (0.1) ( t2+ t1 ) = 0.5 ( t2 + t1 )
t2 + t1 = 4
t2 - t1 = 0.1
2t1 = 3.9 , t1 = 3.9/2 = 1.95 s
therefore
H1 = 5(1.95)² = 19.0125 m.
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