a stone is dropped from the edge of the roof it passes ta widow in 0.1 seconds how far is the roof above top of the window
shray62:
i am going to delete thi app no one is giving answer of my question
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hello friend here is ur ans
given : time. t =0.1 s then since it is falling gravity is positive and initial velocity ,u=0 and final velocity be v , then we have
S=ut+1÷2×g×t^2
since initial velocity , u=0
therefore u×t becomes zero then we are left with
=1/2×g×t^2
=1/2×9.8×(0.1)^2
=4.6×0.1×0.1
=4.6×0.01
=0.046 m
hence the window is 0.046 m below from the roof top
given : time. t =0.1 s then since it is falling gravity is positive and initial velocity ,u=0 and final velocity be v , then we have
S=ut+1÷2×g×t^2
since initial velocity , u=0
therefore u×t becomes zero then we are left with
=1/2×g×t^2
=1/2×9.8×(0.1)^2
=4.6×0.1×0.1
=4.6×0.01
=0.046 m
hence the window is 0.046 m below from the roof top
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