A stone is dropped from the roof of a building . It takes 4 sec to reach the ground . Calculate
1-the height of the building
2-the velocity with which the stone hits the ground
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Hey!
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Time taken to reach ground = 4s
Initial velocity ( u) = 0
Gravity due to acceleration = 9.8 m/s^2
Height of building (h) =?
Let's find final velocity first,
Using first equation of motion,
v - u = gt
v - 0 = 9.8×4
v = 39.2 m/s
Now, h=?
v^2 - u^2 = 2gh
39.2^2 = 2×9.8 × h
1,536.64 = 19.6 × h
h= 78.39
_______________
Hope it helps...!!!
_______________
Time taken to reach ground = 4s
Initial velocity ( u) = 0
Gravity due to acceleration = 9.8 m/s^2
Height of building (h) =?
Let's find final velocity first,
Using first equation of motion,
v - u = gt
v - 0 = 9.8×4
v = 39.2 m/s
Now, h=?
v^2 - u^2 = 2gh
39.2^2 = 2×9.8 × h
1,536.64 = 19.6 × h
h= 78.39
_______________
Hope it helps...!!!
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