A stone is dropped from the top of a 45 m high building .how fast will, it be moving when it reaches the ground ?And what will its velocity be? from grade 9
ers12:
can you send pic
Answers
Answered by
3
since g=10m/s^2
so
u=0
from third equations of motion
v^2=2as
v^2=2×10×45
v= root (2×10×45)
v=2×5×3=30 m/s
so
u=0
from third equations of motion
v^2=2as
v^2=2×10×45
v= root (2×10×45)
v=2×5×3=30 m/s
Answered by
1
The stone is dropped so initial velocity will be 0
So by 3rd eq of motion
So by 3rd eq of motion
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