Question

A stone is dropped from the top of a building of height 45 m. Calculate its velocity , when it srtikes the ground.(Take g=10 m/s2)

Answer 1

Given,

U = 0
V = ?
G = 10m/s²
H= 45m

Using the Newton's 3rd equation of motion

➡V² - U² = 2as

➡V² = (0)² + 2 x 10 x 45

➡$v = \sqrt{900}$

➡$v = 30$

Answer = 30m/s is the striking velocity of ball when it reaches the ground.

Answer 2

Hey mate....

here's the answer..

Hope it helps ❤️